When Django handles a file upload, the file data ends up placed in
request.FILES (for more on the
request object see the documentation for request and response objects). This document explains how files are stored on disk
and in memory, and how to customize the default behavior.
هشدار
There are security risks if you are accepting uploaded content from untrusted users! See the security guide’s topic on User-uploaded content for mitigation details.
Consider a form containing a FileField:
from django import forms
class UploadFileForm(forms.Form):
title = forms.CharField(max_length=50)
file = forms.FileField()
A view handling this form will receive the file data in
request.FILES, which is a dictionary
containing a key for each FileField (or
ImageField, or other FileField
subclass) in the form. So the data from the above form would
be accessible as request.FILES['file'].
Note that request.FILES will only
contain data if the request method was POST, at least one file field was
actually posted, and the <form> that posted the request has the attribute
enctype="multipart/form-data". Otherwise, request.FILES will be empty.
Most of the time, you’ll pass the file data from request into the form as
described in Binding uploaded files to a form. This would look something like:
from django.http import HttpResponseRedirect
from django.shortcuts import render
from .forms import UploadFileForm
# Imaginary function to handle an uploaded file.
from somewhere import handle_uploaded_file
def upload_file(request):
if request.method == 'POST':
form = UploadFileForm(request.POST, request.FILES)
if form.is_valid():
handle_uploaded_file(request.FILES['file'])
return HttpResponseRedirect('/success/url/')
else:
form = UploadFileForm()
return render(request, 'upload.html', {'form': form})
Notice that we have to pass request.FILES
into the form’s constructor; this is how file data gets bound into a form.
Here’s a common way you might handle an uploaded file:
def handle_uploaded_file(f):
with open('some/file/name.txt', 'wb+') as destination:
for chunk in f.chunks():
destination.write(chunk)
Looping over UploadedFile.chunks() instead of using read() ensures that
large files don’t overwhelm your system’s memory.
There are a few other methods and attributes available on UploadedFile
objects; see UploadedFile for a complete reference.
If you’re saving a file on a Model with a
FileField, using a ModelForm
makes this process much easier. The file object will be saved to the location
specified by the upload_to argument of the
corresponding FileField when calling
form.save():
from django.http import HttpResponseRedirect
from django.shortcuts import render
from .forms import ModelFormWithFileField
def upload_file(request):
if request.method == 'POST':
form = ModelFormWithFileField(request.POST, request.FILES)
if form.is_valid():
# file is saved
form.save()
return HttpResponseRedirect('/success/url/')
else:
form = ModelFormWithFileField()
return render(request, 'upload.html', {'form': form})
If you are constructing an object manually, you can assign the file object from
request.FILES to the file field in the
model:
from django.http import HttpResponseRedirect
from django.shortcuts import render
from .forms import UploadFileForm
from .models import ModelWithFileField
def upload_file(request):
if request.method == 'POST':
form = UploadFileForm(request.POST, request.FILES)
if form.is_valid():
instance = ModelWithFileField(file_field=request.FILES['file'])
instance.save()
return HttpResponseRedirect('/success/url/')
else:
form = UploadFileForm()
return render(request, 'upload.html', {'form': form})
If you want to upload multiple files using one form field, set the multiple
HTML attribute of field’s widget:
from django import forms
class FileFieldForm(forms.Form):
file_field = forms.FileField(widget=forms.ClearableFileInput(attrs={'multiple': True}))
Then override the post method of your
FormView subclass to handle multiple file
uploads:
from django.views.generic.edit import FormView
from .forms import FileFieldForm
class FileFieldFormView(FormView):
form_class = FileFieldForm
template_name = 'upload.html' # Replace with your template.
success_url = '...' # Replace with your URL or reverse().
def post(self, request, *args, **kwargs):
form_class = self.get_form_class()
form = self.get_form(form_class)
files = request.FILES.getlist('file_field')
if form.is_valid():
for f in files:
... # Do something with each file.
return self.form_valid(form)
else:
return self.form_invalid(form)
When a user uploads a file, Django passes off the file data to an upload
handler – a small class that handles file data as it gets uploaded. Upload
handlers are initially defined in the FILE_UPLOAD_HANDLERS setting,
which defaults to:
["django.core.files.uploadhandler.MemoryFileUploadHandler",
"django.core.files.uploadhandler.TemporaryFileUploadHandler"]
Together MemoryFileUploadHandler and
TemporaryFileUploadHandler provide Django’s default file upload
behavior of reading small files into memory and large ones onto disk.
You can write custom handlers that customize how Django handles files. You could, for example, use custom handlers to enforce user-level quotas, compress data on the fly, render progress bars, and even send data to another storage location directly without storing it locally. See Writing custom upload handlers for details on how you can customize or completely replace upload behavior.
Before you save uploaded files, the data needs to be stored somewhere.
By default, if an uploaded file is smaller than 2.5 megabytes, Django will hold the entire contents of the upload in memory. This means that saving the file involves only a read from memory and a write to disk and thus is very fast.
However, if an uploaded file is too large, Django will write the uploaded file
to a temporary file stored in your system’s temporary directory. On a Unix-like
platform this means you can expect Django to generate a file called something
like /tmp/tmpzfp6I6.upload. If an upload is large enough, you can watch this
file grow in size as Django streams the data onto disk.
These specifics – 2.5 megabytes; /tmp; etc. – are “reasonable defaults”
which can be customized as described in the next section.
There are a few settings which control Django’s file upload behavior. See File Upload Settings for details.
Sometimes particular views require different upload behavior. In these cases,
you can override upload handlers on a per-request basis by modifying
request.upload_handlers. By default, this list will contain the upload
handlers given by FILE_UPLOAD_HANDLERS, but you can modify the list
as you would any other list.
For instance, suppose you’ve written a ProgressBarUploadHandler that
provides feedback on upload progress to some sort of AJAX widget. You’d add this
handler to your upload handlers like this:
request.upload_handlers.insert(0, ProgressBarUploadHandler(request))
You’d probably want to use list.insert() in this case (instead of
append()) because a progress bar handler would need to run before any
other handlers. Remember, the upload handlers are processed in order.
If you want to replace the upload handlers completely, you can assign a new list:
request.upload_handlers = [ProgressBarUploadHandler(request)]
تبصره
You can only modify upload handlers before accessing
request.POST or request.FILES – it doesn’t make sense to
change upload handlers after upload handling has already
started. If you try to modify request.upload_handlers after
reading from request.POST or request.FILES Django will
throw an error.
Thus, you should always modify uploading handlers as early in your view as possible.
Also, request.POST is accessed by
CsrfViewMiddleware which is enabled by
default. This means you will need to use
csrf_exempt() on your view to allow you
to change the upload handlers. You will then need to use
csrf_protect() on the function that
actually processes the request. Note that this means that the handlers may
start receiving the file upload before the CSRF checks have been done.
Example code:
from django.views.decorators.csrf import csrf_exempt, csrf_protect
@csrf_exempt
def upload_file_view(request):
request.upload_handlers.insert(0, ProgressBarUploadHandler(request))
return _upload_file_view(request)
@csrf_protect
def _upload_file_view(request):
... # Process request
Jul 27, 2022